Enzymes Pharmacodynamics😊

  • Definition : Specialized proteins that act as biological catalyst
  • Exception : Ribozymes (RNA)
    • GRPS
      • Ribozyme
        Location
        Function
        Group II introns
        -
        RNA splicing
        Ribonuclease P
        Nucleus
        Post-transcriptional modification of tRNA
        Peptidyl transferase
        28S rRNA
        Translation
        snRNA
        Spliceosome
        RNA splicing

Enzyme Mechanism of Action

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  • Binding Sites:
    • Active site:
      • Substrate binding.
    • Allosteric site:
      • Site for regulators/modifiers.

Free Energy Change (ΔG):

  • Formula:
    • ΔG = Energy of reactants − Energy of products
  • Effect of Enzyme:
    • Lowers activation energy.
    • No change in ΔG.
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Enzyme–Substrate Complex Theories:

  • Fish (Emil Fischer) Locked with a key and brought to land by koshy (Koshland)

1. Emil-Fischer’s Template Theory

  • Lock and Key Mechanism
    • Substrate fits perfectly into the enzyme’s active site.
    • Lock and key cannot explain dynamic changes
    • notion image

2.Koshland’s Induced Fit Theory:

  • Active site undergoes conformational change
    • upon substrate binding.
  • Ensures a more precise fit.
    • notion image

Kinetics of Elimination

Half-Life (t½)

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  • Definition:
    • Time for plasma concentration to reduce by half
  • t1/2 = 0.693 / K
    • (K = elimination rate constant)
    • Since K = CL / Vd,
  • t1/2 = (0.693 × Vd) / CL
  • First-order kinetics:
    • t½ is constant regardless of dose
    • Example:
      • If t½ = 6 hours, after 24 hours (4 t½):
        • Drug remaining = 6.25%
        • Drug eliminated = 93.75%
  • Clinical Use:
    • Guides dosing interval/frequency
  • Mnemonic: HalfLife = Learnt To make ViDeo CLear
    • t1/2 = ln(2) Vd/CL = 0.7 Vd/CL
    • E.g. In the above case, if we need to calculate t1/2 –
    • t1/2 = 0.7 X Vd/CL or 0.7/kE = 0.7/0.015 = 46.7 hr

Equilibrium Constant (Keq):

  • A + B → C + D (→ K1; ←K2)
  • Keq = K1/K2 ;
  • Keq = [Products]/[Substrates]
  • Independent of enzyme action.

Order of Kinetics

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Mnemonic:
  • First Order → depend on first concentration
  • Zero Order → Zero equation → same amount is reduced
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Feature
Zero-Order Kinetics
First-Order Kinetics
Elimination Rate
Amount is constant
Fraction is constant
Rate
Rate = Constant
Rate ∝ Plasma Conc. (PC)
Clearance (CL)
CL ∝ 1/PC
Constant
Half-Life (t1/2)
t1/2 ∝ PC
Constant
ie, Response to ↑↑ [drug]
Clearance ↓↓ & t1/2 → ↑↑
Rate ↑↑
Limit
Capacity-limited

ie Liver/kidney are saturated
Flow-limited
Zero-Order Drugs
Mnemonic: Zero WATT Power
Warfarin
Alcohol/Aspirin
Theophylline
Tolbutamide
Phenytoin
Most of the drugs
first = 
flow-limited,
fraction constant
first = fixed t1/2
first = fixed CL
Serum drug concentration (Cp) vs time graph
Straight line

Zero - amount and rate constant
Curved line
  • Important Example:
    • After 270 minutes (third 90-minute cycle):
      • 78.125 mg × 0.375 = 29.297 mg eliminated,
      • 78.125 - 29.297 = 48.828 mg remains.
    • After 360 minutes (fourth 90-minute cycle):
      • 48.828 × 0.375 = 18.310 mg eliminated,
      • 48.828 - 18.310 = 30.518 mg remains after 6 hours.

Michaelis-Menten kinetics

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  • Graph: Hyperbola curve
  • Michaelis-Menten Equation:
    • V1 = (Vmax × [S])
      (Km+[S])

Michaelis Constant (Kₘ):

  • [S] at Vₘₐₓ/2
  • Inversely proportional to enzyme’s affinity for substrate
  • High Km → Bad ❌
    • ↓ Affinity
    • More substrate is needed to achieve half-maximal velocity
  • Ideal substrate: Low Km
  • If Km is 100 micromol:
    • Substrate concentration of 100 micromol is needed.
    • For the enzyme to achieve ½ maximal velocity.
  • If Km is 1000 micromol:
    • Substrate concentration of 1000 micromols is needed.
    • For the enzyme to achieve the same ½ Vmax.

Allosteric Enzyme

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Factors Affecting Rate of Reaction:

1. Substrate Concentration [S][S]:

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  • Initial stage:
    • 1st order kinetics: Rate ∝ [S]
  • Later stage:
    • 0 order kinetics: Active sites saturated, Rate ≠ [S]

2. Enzyme Concentration [E][E]:

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  • Directly proportional
  • Enzyme concentration doubles,
    • rate of reaction/velocity doubles
In a reaction, the substrate is available in a concentration that is 1000 times the Km value of the enzyme. After 9 minutes of reaction, 1% of substrate is converted to product (12 µg/ml). If the concentration of the enzyme is changed to 1/3 and concentration of substrate is doubled, what is the time taken to convert the substrate into the same amount of product (12 µg/ml)?
  • Options:
      1. 9 minutes
      1. 4.5 minutes
      1. 27 minutes
      1. 13.5 minutes
        1. ANS
          • 27 minutes

          Applied Aspect:

          • In a reaction mixture, if S = 1000 x Km
            • In such a mixture, it follows zero order kinetics
            • ie, velocity is independent of further added substrates

3. Temperature and pH:

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  • Graph shows enzyme activity rises, peaks, then falls due to denaturation
  • Optimum conditions:
    • At Vmax
      • Optimum Temperature:
        • 35–40°C
      • Optimum pH: 5–9

Applied Qs

  • If temperature is increased 10 times, what is rate of reaction
💡
  • Q₁₀ Effect:
    • 10°C ↑ = 2× increase in rate of reaction
  • Mnemonic: Kuttan likes temperature

Pharmacodynamics

Types of Enzyme Inhibition

  • A. Reversible (Pharmacological agents).
      1. Competitive.
      1. Uncompetitive.
      1. Mixed.
          • Noncompetitive is a special type of mixed inhibition.
  • B. Irreversible.

Lineweaver-Burke Plot/Double Reciprocal Plot

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  • Double reciprocal plot
    • 1/S on X-axis → 1/Km
    • 1/V on Y-axis → 1/Vmax
    • Straight line
    • Type
      Km
      Vmax
      Lineweaver-Burke Plot
      Competitive
      -
      Lines intersect at Y-axis
      (same Vmax)
      Non-Competitive
      -

      Lines intersect at X-axis
      (same Km)

Catalytic Constant:

  • AKA turnover number = Enzyme efficiency
  • Kcat = [Vmax]/ [Et]
    • Et = Total enzyme concentration.
  • Catalytic efficiency = Kcat/Km
  • Kcat α Efficiency of enzyme
  • Km α 1 / Efficiency of enzyme
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Feature
Competitive (Reversible)
Uncompetitive inhibition
Non -competitive
Mixed inhibition
Competitive (Irreversible)
Mnemonic
Competetive → V E (WE are) constant
U → Parallel shift → both ↓
V shape
Non comp → Normal Km
Mixed → reversal of normal →
Vmax ↓, Kmax ↑
Shape of line
X shape
Parallelly shifted line.
V shaped
X shaped
Vmax
N
↓↓
↓↓
↓↓
Km
↑↑
↓↓
N
↑↑
Substrate Resemblance
Yes
Reduces the probability of ES complex and Product formation.
No
No

special type of mixed inhibitor.
No
Yes
Reversibility
Reversible
Reversible or irreversible (context-dependent)
Irreversible
(or high affinity)
Overcome by ↑[S]
Can be overcome
Cannot be overcome → more ESI complex
Cannot be overcome
Cannot be overcome
Cannot be overcome
Binding Site
Active site
Distinct (allosteric) site
Both free enzymes and enzyme substrate complexes.
Active site
Bind E-S Complex
No
Yes
Yes
Yes → Binds both ES complex and an ESI complex
No
Competition → We Become first
No competition → We become less
Competition → We Become first
No competition → We become less

Mneumonic

  • Competitive
    • Kilometer (Km) increases
    • But WE (Vmax, Efficacy) r constant
    • we can OVERCOME by increasing effort (↑ substrate → reverses)
    • Competitive - X graph
  • Non-competitive inhibitor
    • Non-Kmpitivie → No Km change
    • If no competition → No Victory (Vmax ↓↓)

Q. Identify the type of inhibition.

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  • A. Competitive inhibition.
  • B. Uncompetitive inhibition.
  • C. Mixed inhibition.
  • D. Non-competitive inhibition.